(-2)^3+2^3/3-3^2+2*4

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Solution for (-2)^3+2^3/3-3^2+2*4 equation: 


(-2)^3+(2^3)/3-3^2+2*4 = 0

(2^3)/3-3^2+2*4-8 = 0

8/3-3^2+2*4-8 = 0

2*4-3^2-8+8/3 = 0

2*4-3^2-16/3 = 0

2*4-9-16/3 = 0

2*4-43/3 = 0

8-43/3 = 0

-19/3 = 0

L <> R

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